あるファイルを require したときにその結果が空のオブジェクトとして返される問題
module.exports first, lazy require, dependency injectionなどの解決方法がある
import sys import re MAPPING = { 'core_read.cpp': 'core_io.cpp', 'core_write.cpp': 'core_io.cpp', } # Directories with header-based modules, where the assumption that .cpp files # define functions and variables declared in corresponding .h files is # incorrect. HEADER_MODULE_PATHS = [ 'interfaces/' ] def module_name(path): if path in MAPPING: path = MAPPING[path] if any(path.startswith(dirpath) for dirpath in HEADER_MODULE_PATHS): return path if path.endswith(".h"): return path[:-2] if path.endswith(".c"): return path[:-2] if path.endswith(".cpp"): return path[:-4] return None files = dict() deps: dict[str, set[str]] = dict() RE = re.compile("^#include <(.*)>") # Iterate over files, and create list of modules for arg in sys.argv[1:]: module = module_name(arg) if module is None: print("Ignoring file %s (does not constitute module)\n" % arg) else: files[arg] = module deps[module] = set() # Iterate again, and build list of direct dependencies for each module # TODO: implement support for multiple include directories for arg in sorted(files.keys()): module = files[arg] with open(arg, 'r', encoding="utf8") as f: for line in f: match = RE.match(line) if match: include = match.group(1) included_module = module_name(include) if included_module is not None and included_module in deps and included_module != module: deps[module].add(included_module) # Loop to find the shortest (remaining) circular dependency have_cycle: bool = False while True: shortest_cycle = None for module in sorted(deps.keys()): # Build the transitive closure of dependencies of module closure: dict[str, list[str]] = dict() for dep in deps[module]: closure[dep] = [] while True: old_size = len(closure) old_closure_keys = sorted(closure.keys()) for src in old_closure_keys: for dep in deps[src]: if dep not in closure: closure[dep] = closure[src] + [src] if len(closure) == old_size: break # If module is in its own transitive closure, it's a circular dependency; check if it is the shortest if module in closure and (shortest_cycle is None or len(closure[module]) + 1 < len(shortest_cycle)): shortest_cycle = [module] + closure[module] if shortest_cycle is None: break # We have the shortest circular dependency; report it module = shortest_cycle[0] print("Circular dependency: %s" % (" -> ".join(shortest_cycle + [module]))) # And then break the dependency to avoid repeating in other cycles deps[shortest_cycle[-1]] = deps[shortest_cycle[-1]] - set([module]) have_cycle = True sys.exit(1 if have_cycle else 0)